4/x^2-5/x

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Solution for 4/x^2-5/x equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4/(x^2)-(5/x) = 0

4/(x^2)-5*x^-1 = 0

4*x^-2-5*x^-1 = 0

t_1 = x^-1

4*t_1^2-5*t_1^1 = 0

4*t_1^2-5*t_1 = 0

DELTA = (-5)^2-(0*4*4)

DELTA = 25

DELTA > 0

t_1 = (25^(1/2)+5)/(2*4) or t_1 = (5-25^(1/2))/(2*4)

t_1 = 5/4 or t_1 = 0

t_1 = 0

x^-1+0 = 0

x^-1 = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x należy do O

t_1 = 5/4

x^-1-5/4 = 0

1*x^-1 = 5/4 // : 1

x^-1 = 5/4

-1 < 0

1/(x^1) = 5/4 // * x^1

1 = 5/4*x^1 // : 5/4

4/5 = x^1

x = 4/5

x = 4/5

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